Won't pass final test

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What the heck? This won't pass the final test, but I can't make it fail manually. public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String sN = reader.readLine(); int n = Integer.parseInt(sN); if((!(n > 0)) || (!(n < 1000))){ System.out.println(""); }else if((n % 2 == 0) && (n < 10)){ System.out.println("even single-digit number"); }else if((!(n % 2 == 0)) && (n < 10)){ System.out.println("odd single-digit number"); }else if((n % 2 == 0) && (n < 100)){ System.out.println("even two-digit number"); }else if((!(n % 2 == 0)) && (n < 100)){ System.out.println("odd two-digit number"); }else if((n % 2 == 0) && (n < 1000)){ System.out.println("even three-digit number"); }else if((!(n % 2 == 0)) && (n < 1000)){ System.out.println("odd three-digit number"); } } }

Enter an integer from the keyboard in the range 1 - 999. Display a string description as follows:
"even single-digit number" - if the number is even and has one digit,
"odd single-digit number" - if the number is odd and has one digit,
"even two-digit number" - if the number is even and has two digits,
"odd two-digit number" - if the number is odd and has two digits,
"even three-digit number" - if the number is even and has three digits,
"odd three-digit number" - if the number is odd and has three digits.
If the entered number does not fall in the range 1 - 999, don't display anything.

Example for 100:
even three-digit number

Example for 51:
odd two-digit number

Requirements:

The program should read one number from the keyboard.
The program should use System.out.println() or System.out.print()..
If the number is even and has one digit, display "even single-digit number".
If the number is odd and has one digit, display "odd single-digit number".
If the number is even and has two digits, display "even two-digit number".
If the number is odd and has two digits, display "odd two-digit number".
If the number is even and has three digits, display "even three-digit number".
If the number is odd and has three digits, display "odd three-digit number".
If the entered number doesn't fall in the range 1 - 999, don't display anything
The program should display a string description of the number and nothing else.

package com.codegym.task.task04.task0427; /* Describing numbers */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String sN = reader.readLine(); int n = Integer.parseInt(sN); if((!(n > 0)) || (!(n < 1000))){ System.out.println(""); }else if((n % 2 == 0) && (n < 10)){ System.out.println("even single-digit number"); }else if((!(n % 2 == 0)) && (n < 10)){ System.out.println("odd single-digit number"); }else if((n % 2 == 0) && (n < 100)){ System.out.println("even two-digit number"); }else if((!(n % 2 == 0)) && (n < 100)){ System.out.println("odd two-digit number"); }else if((n % 2 == 0) && (n < 1000)){ System.out.println("even three-digit number"); }else if((!(n % 2 == 0)) && (n < 1000)){ System.out.println("odd three-digit number"); } } }

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Joseph Haynes

Level 2 , United States of America, United States

Expert

29 December 2019, 19:11

Thank you. Your solutions worked.

Niels Fardeau

Level 13 , Avignon, France

29 December 2019, 13:45

Don't forget that displaying "" is still displaying something. Just do nothing if the number is out of range and your code will pass the last check.

Anthony Chalk

Level 30 , London, United Kingdom

29 December 2019, 11:46

Get rid of line 18