how to solve this ?

Question about the task

Task No. 7 about integer type conversions

Resolved

Remove unnecessary operators to get the correct answer: 1234567
long l = (byte)1234_564_890L;
int x = (byte)0b1000_1100_1010;
double m = (byte)110_987_654_6299.123_34;
float f = (byte)l++ + 10 + ++x - (float)m;
l = (long) f / 1000;

Requirements:

The program should display text on the screen.
Don't change the screen output command.
The main() method must contain a long variable l.
The main() method must contain an int variable x.
The main() method must contain a double variable m.
The main() method must contain a float variable f.
Don't change the initial value of the variables during initialization. You can only change the cast operators.
The program should display 1234567.

package com.codegym.task.task10.task1007; /* Task No. 7 about integer type conversions */ public class Solution { public static void main(String[] args) { long l = (byte) 1234_564_890L; System.out.println(l); int x = (byte) 0b1000_1100_1010; System.out.println(x); double m = (byte) 110_987_654_6299.123_34; System.out.println(m); float f = (byte) l++ + 10 + ++x - (float) m; System.out.println(f); l = (int) f / 1000; System.out.println(l); } }

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Thang Za Thang

Level 18 , Melbourne, Australia

5 July 2020, 01:36

Expected Johannes to be in these comments : (

Dhruv Kale

Level 22 , Vadodara, India

15 June 2019, 04:31

solution

long l = (int) 1234_564_890L; int x = (short) 0b1000_1100_1010; double m = (short) 110_987_654_6299.123_34; float f = (float) l++ + 10 + ++x - (float) m; l = (int) f / 1000; System.out.println(l);

+28

Profj

Level 20 , Lagos, Nigeria

15 June 2019, 06:34

Perfect! Thanks.

Carlos Cortázar

Level 17 , Madrid, Spain

12 September 2019, 14:27

Thanks Dhruv!!! Now I just ought to understand it!!!

MecoS Full Stack Developer at Microsoft

17 December 2019, 12:57

Thanks.. maybe this cast of number aren't my best skill...

Nicola

Level 17 , Vienna, Austria

13 June 2019, 19:51

l = (long) f / 1000; //the reminder is ignored so f can be something like 1234567170

ulmas9025

Level 20 , Tashkent, Uzbekistan

11 June 2019, 04:52

public class Solution { public static void main(String[] args) { double d = (short) 2.50256e2d; char c = (short) 'd'; short s = (short) 2.22; int i = 150000; float f = 0.50f; double result = f + (i / c) - (d * s) - 500e-3; System.out.println("result: " + result); } }

KenCanKode Backend Developer

27 May 2019, 09:44

Check the results in relation to 'double m'

Tayyab Mubeen

Level 16 , Lahore, Pakistan

1 November 2018, 18:22

check line number 10 , 11 and 16

Roy

Level 22 , Bangkok, Thailand

22 April 2019, 23:35

10,12 and 16**