please just me what was wrong in my output

Question about the task

Escaping characters

Java Syntax, Level 3, Lesson 6

Under discussion

in 2nd line

Display the following text (two lines):
This is a Windows path: "C:\Program Files\Java\jdk1.8.0_172\bin" This is a Java string: \"C:\\Program Files\\Java\\jdk1.8.0_172\\bin\"

Hint:
\" – Escape sequence for double quote character.
\\ – Escape sequence for a backslash (\) character.

Requirements:

The program should output text.
Two lines must be displayed.
The first line of text should be: This is a Windows path: "C:\Program Files\Java\jdk1.8.0_172\bin"
The second line of text should be: This is a Java string: \"C:\\Program Files\\Java\\jdk1.8.0_172\\bin\"

package com.codegym.task.task03.task0316; /* Escaping characters */ public class Solution { public static void main(String[] args) { System.out.println("This is a Windows path: \"C:\\Program Files\\Java\\jdk1.8.0_172\\bin\""); System.out.println("This is a Java string: \\\"C:\\\\Program Files\\\\Java\\\\jdk1.8.0_172\\\\bin\"");//write your code here } }

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Brice

Level 8 , Douala, Cameroun

25 November 2018, 19:12

here: System.out.println("This is a Windows path: \"C:\\Program Files\\Java\\jdk1.8.0_172\\bin\""); System.out.println("This is a Java string: \\\"C:\\\\Program Files\\\\Java\\\\jdk1.8.0_172\\\\bin\\\"");

Ultimate.ITpro

Level 5 , Bandar Emam Khomeyni, Iran, Islamic Republic of

14 October 2018, 07:52

//  -->   ( \" = " ) , ( \\ = \ ) , ( \\\\ = \\) , ( \\\" = \")
        System.out.println("This is a Windows path: \"C:\\Program Files\\Java\\jdk1.8.0_172\\bin\"");
        System.out.println("This is a Java string: \\\"C:\\\\Program Files\\\\Java\\\\jdk1.8.0_172\\\\bin\\\"");

Ankush Rajput

Level 25 , Bhopal, India

11 October 2018, 16:27

Check your output carefully. In second line, you are missing a \ after "bin". No \ is being shown in output.

Rad

Level 8 , Maidstone, United Kingdom

11 October 2018, 16:39

thank you