output is correct but still not passing

Question about the task

Going national

Java Syntax, Level 8, Lesson 11

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I am getting correct output but still not passing can understand why ?

package com.codegym.task.task08.task0823; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; /* Going national */ public class Solution { public static void main(String[] args) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String s = reader.readLine(); char[] sToChar = s.toCharArray(); char empty = ' '; char stop = '.'; char[] word = new char[sToChar.length]; int count = 0; String convertedText; String resultWords =""; for (char temp : sToChar) { if (temp == empty) { count = 0; convertedText = new String(word); word = new char[sToChar.length]; if (resultWords.isEmpty()) { resultWords = convertedText.trim(); System.out.print(resultWords); } else { resultWords = convertedText.trim(); System.out.print(" " + resultWords); } } else { if (count == 0) { word[0] = Character.toUpperCase(temp); } else { word[count] = temp; } count++; if (temp == stop) { convertedText = new String(word); if (resultWords.isEmpty()) { resultWords = convertedText.trim(); System.out.println(resultWords); } else { resultWords = convertedText.trim(); System.out.print(" " + resultWords); } } } } } }

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Art

Level 13 , Chisinau, Moldova, Republic of

14 March 2020, 19:24

public class Solution { public static void main(String[] args) throws IOException { Scanner scan = new Scanner(System.in); String s = scan.nextLine(); char arr[] = new char[s.length()]; for (int i = 0; i < s.length(); i++) { char c = s.charAt(i); arr[i] = c; } char first = arr[0]; char firstc = Character.toUpperCase(first); arr[0] = firstc; for (int i = 0; i < s.length(); i++) { char c = arr[i]; if (Character.toString(c).matches(" ")) { i = i + 1; char d = arr[i]; char w = Character.toUpperCase(d); arr[i] = w; } } System.out.println(arr); } }

Johannes

Level 27 , Centurion, Pretoria, South-Africa

11 March 2020, 17:30

Wayyyyy too complex. Try this: (I should not give the solution, but there's so much overcomplex assistance in the help, and we have not done this yet, that i feel everyone is just getting confused. You simple split the string, trimming it for 1 or more spaces "\s+" and because it's a backslash, you need another backslash in front of it. I.e "\\s+" (the plus is more than one space). Then do a loop, where you uppercase the substring from character 0 to just before character 1: substring(0,1) Then assign this (copy) to another string, as you don't modify the original string when doing this (original will stay the same). Add the rest of the string to the word (substring(1) means from array position 1 to end of string. BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String s = reader.readLine(); String[] words = s.trim().split("\\s+"); String sentence=""; for (String f: words){ String j = f.toUpperCase().substring(0,1) + f.substring(1); sentence += j + " "; } System.out.println(sentence); } }

Skynet

Level 40 , USA

11 March 2020, 08:11

You're overcomplicating things. Try this: Create another String variable and assign the result of variable s + toUpperCase() to it. Then, use the charAt() method to print the first letter of your new String variable, but make sure you use print() not println(). Then, create a standard for loop and start it with int i = 1 (since you've already printed one letter). "i" condition should be based on the length of your first variable s. Then, create a single if else statement. In the if, check whether the i - 1 of variable s is equal to a space. Basically, check whether a previous letter (index i - 1) is a space. If the condition is true then use the standard print() method to print the i of variable z, using the charAt() method. If the condition is false, use the else statement to print the i of variable s, using the charAt() method.

Attila

Level 25

8 March 2020, 13:28

useful

Your program does not work correctly, if there are multiple space between the words. Unfortunately this is a condition as well..

Goran

Level 41 , Belgrade, Serbia

8 March 2020, 13:58

But I cant see more spaces then it should be. I even tried to type in browser code and getting same as on picture :/

Attila

Level 25

9 March 2020, 05:19

Aha. The program should work without the '.' character at the end of the string. Right now if you dont put the '.' at the end of the input, it will not print out the last word. Try to run your Program with the Debugger tool.

Goran

Level 41 , Belgrade, Serbia

9 March 2020, 06:24

I thought '.' was part of task condition. And that is used to know when it is end of input