What is wrong with my code? how can i join two min(a,b,c,d) method with min(a,b) method?

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package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { //write your code here int min2; if (a<=b && a<=c && a<= d) min2 = a; else if (b<=a && b<=c && b<=d) min2 = b; else if (c<=a && c<= b && c<=d) min2 = c; else min2 = d; return min2; } public static int min(int a, int b) { if (a<=b) min1 = a; else min1 = b; return min1; //write your code here } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

Write a function that computes the minimum of four numbers.
The function min(a, b, c, d) should use (call) the function min(a, b)

Hint:
You need to write the body of the two existing min functions.

Requirements:

The program should display text on the screen.
The min methods should not display text on the screen.
The main method should call min(a, b) and min(a, b, c, d).
The main method should display the result of the min methods. Each time, on a new line.
The min(a, b) method must return the minimum of the numbers a and b.
The min(a, b, c, d) method must use the min(a, b) method.
The min(a, b, c, d) method must return the minimum of the numbers a, b, c, and d.

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { //write your code here int min2; if (a<=b && a<=c && a<= d) min2 = a; else if (b<=a && b<=c && b<=d) min2 = b; else if (c<=a && c<= b && c<=d) min2 = c; else min2 = d; return min2; } public static int min(int a, int b) { int min1 ; if (a<=b) min1 = a; else min1 = b; return min1; //write your code here } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

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143_Ritik Awachat

Level 4

16 September 2020, 04:14

You are doing well. What you have to do is first find min if a and b if (a <= b) returns a else returns b. And for bigger one if (min(a,b) <= min(c,d)) returns min(a,b) else returns min(c,d). Hope this will work. Wish you the best.

Belinda

Level 4 , Portland, United States

13 May 2020, 11:30

min(int a, int b, int c, int d) in this method you wrote code to determine the minimum of a and b again. Since you already figured out the minimum of a and b in min(int a, int b)...just put that method -- min(a,b); where you have the a,b code repeated.

Faisal Ahmed

Level 13 , Bangalore, India

26 April 2020, 02:03

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { //write your code here int m1 = min(a, b);

Sharif Sharipov

Level 20 , Atlanta, United Statess

23 January 2020, 20:57

public static int min(int a, int b, int c, int d) { //write your code here return min(a,min(b,min(c,d))); } You should call the second method for the first one.

Khurram

Level 16 , Lahore, Pakistan

22 October 2018, 06:38

the min function with two parameters, returns the minimum of two numbers, use that returned number