; expected

Question about the task

Escaping characters

Java Syntax, Level 3, Lesson 6

Under discussion

where is ; expected man

Display the following text (two lines):
This is a Windows path: "C:\Program Files\Java\jdk1.8.0_172\bin" This is a Java string: \"C:\\Program Files\\Java\\jdk1.8.0_172\\bin\"

Hint:
\" – Escape sequence for double quote character.
\\ – Escape sequence for a backslash (\) character.

Requirements:

The program should output text.
Two lines must be displayed.
The first line of text should be: This is a Windows path: "C:\Program Files\Java\jdk1.8.0_172\bin"
The second line of text should be: This is a Java string: \"C:\\Program Files\\Java\\jdk1.8.0_172\\bin\"

package com.codegym.task.task03.task0316; /* Escaping characters */ public class Solution { public static void main(String[] args) { String s = """C:""Program Files""java""jdk1.8.0_172""bin"""; String v = """C:\\\Program\\\Files\\\Java\\\jdk1.8.0_172\\\bin"""; System.out.println("This is a Windows path:" + s); System.out.println("This is a Java string:" + v);//write your code here } }

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Gellert Varga

Level 23 , Szekesfehervar, Hungary

19 April 2020, 15:37

Why do you use so many quotation marks at the beginning of a string? (3 pieces). You need one. - The exception is created by the \ character. So, if you want to display some extra character in the string (quotation mark or backslash), you need to put a \ before that. For example. - For displaying this: something you need to write this in the code: String s = "something"; - For displaying this: "something" you need to write this in the code: String s = "\"something\"";