What is wrong with this did not understand? plz help me

Question about the task

Sum of the digits of a three-digit number

Java Syntax, Level 3, Lesson 12

Resolved

What i do/

Write the code for sumDigitsInNumber(int number). The method takes a three-digit whole number. You need to calculate the sum of the digits of this number, and then return the result.

Consider this example:
The sumDigitsInNumber method is called with the argument 546.

Example output:
15

Requirements:

The program must not read data from the keyboard.
The sumDigitsInNumber(int) method must be public and static.
The sumDigitsInNumber method must return an int.
The sumDigitsInNumber method should not display anything.
The sumDigitsInNumber method must return the sum of all digits in the parameter number.

package com.codegym.task.task01.task0132; /* Sum of the digits of a three-digit number */ public class Solution { public static void main(String[] args) { System.out.println(sumDigitsInNumber(546)); } public static int sumDigitsInNumber(int number) { //write your code here int sum; int n; sum = 0; while (number>=0){ n = number%10; sum = sum + n; number = number / 10 + number / 10 + number / 10; break; } return sum; } }

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kar-fai chow

Level 8 , Hong Kong, Hong Kong

17 November 2020, 06:55

I think the while loop is an interesting take on this I think you should just do " number = number / 10 " once in the while loop The first pass will change number to 54 The second pass will change number to 5 And the final pass will change number to 0, which will stop the while loop oh and you should change the condition to " number>0 " rather than " number>=0 "

Aleksander

Level 6 , Slupsk, Poland

12 April 2020, 23:02

package com.codegym.task.task01.task0132; /* Sum of the digits of a three-digit number */ public class Solution { public static void main(String[] args) { System.out.println(sumDigitsInNumber(546)); } public static int sumDigitsInNumber(int number) { return number == 0 ? 0: number % 10 + sumDigitsInNumber(number / 10); } }

GoldenDevil

Level 4 , Germany

4 November 2018, 12:05

solution

u don't need the break here and u don' even need to define a second integer (n). u already defined int sum; which is the same as int sum = 0; so delete line 17. try this: while(number > 0) { sum = sum + number % 10; number = number /10; } return sum;

BennyGreen

Level 4 , France

3 November 2018, 12:04

writing "number = number /10 + number/10 + number/10;" is equal to "number = number/3.3333" so it can't be the right formula. my method was to declare 3 int called "hundreds", "tens" and "units" and then trying to find out how to calculate those. After that it is easy to sum "hundreds", "tens" and "units" to get the right number to return. I did not use a while loop. But you can use a while loop, and I say your while loop starts in a pretty good way. But "number = number /10 + number/10 + number/10;" is not the right formula though it's pretty close to the solution...