CodeGym/Help with Java Tasks/I tried multiple scenarios including negatives and still ...

Level 13

Carrollton

14.11.2018
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17comments

I tried multiple scenarios including negatives and still no luck

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I am approaching this in a different way than what has been posted by others. I ran multiple scenarios with no issues, IntelliJ passed the assignment but I couldn't get it to show complete, so I tried to submit it through the web, and it will not pass saying that I need to display the middle number. whats wrong????

package com.codegym.task.task04.task0441; /* Somehow average */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader rd = new BufferedReader(new InputStreamReader(System.in)); int a =Integer.parseInt(rd.readLine()); int b = Integer.parseInt(rd.readLine()); int c = Integer.parseInt(rd.readLine()); System.out.println(MidInt(a, b, c)); } static int MidInt(int a, int b, int c){ int maxnum= Math.max(Math.max(a, b), Math.max(b, c)); int minnum=Math.min(Math.min(a, b),Math.min(b, c)); int x =(a+b+c); int midnum = x-maxnum-minnum; return midnum; } }

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M Harsha Vinay

Level 5 , Khammam, India

30 May 2019, 11:46

that was fine and it worked for me

Fadi AlSaidi

Level 13 , Carrollton, United States

16 November 2018, 18:05

package com.codegym.task.task04.task0441; /* Somehow average */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader rd = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(rd.readLine()); int b = Integer.parseInt(rd.readLine()); int c = Integer.parseInt(rd.readLine()); if (a >= b && a <= c) { System.out.println(a); } else if (b >= a && b <= c) { System.out.println(b); } else if (c>= a && c<=b){ System.out.println(c); } else if (a==b || a == c){ System.out.println(a); } else if (b==a || b == c){ System.out.println(b); } else if (c==a || c == b){ System.out.println(c); } else{ System.out.println(a); } } }

Thomas

Level 12 , Scottsdale, United States

3 June 2019, 21:17

Issue: The program should display the middle number of the three numbers. Test the program with the numbers 3, 2, and 1. Expected output: 2

Vadim

Level 8 , Hounslow, United Kingdom

6 April 2020, 22:03

That's the correct version! ;) if (a >= b && a <= c) { System.out.println(a); } else if (b >= a && b <= c) { System.out.println(b); } else if (c >= a && c <= b) { System.out.println(c); } else if (a > b && b > c && c != a) { System.out.println(b); } else if (a > b && b < c && c < a) { System.out.println(c); } else if (a == b || a == c) { System.out.println(a); } else if (b == a || b == c) { System.out.println(b); } else if (c == a || c == b) { System.out.println(c); } else { System.out.println(a); }

Hoist

Level 32 , San Diego, United States

5 October 2021, 02:05

yep. middle number when I tried it many times )

Michael Martin

Level 19 , Arlington, United States

14 November 2018, 14:15

Does this task require the MidInt() method? If not, then you are making this way too complicated. For instance: if ((a > b) && (a < c)) then a is the middle number. You can do the same test for all the numbers.

Fadi AlSaidi

Level 13 , Carrollton, United States

15 November 2018, 02:23

I tried using if statement with no luck. even though I never ran into an issue identifying the middle number. I am just gonna right this one off. Thank you Michael for you help

Michael Martin

Level 19 , Arlington, United States

15 November 2018, 04:29

Post your code, so we can look at it.

Fadi AlSaidi

Level 13 , Carrollton, United States

16 November 2018, 18:07

sorry, couldn't change the original ones so i posted the code on the replay window. keep in mind that the condition requires a little more than the middle number, thats why i had all those else if. Howevr, thank you for being therefore the likes of me Michael

Michael Martin

Level 19 , Arlington, United States

16 November 2018, 19:13

try this: int middle = 0; if (((a > b) && (a < c)) || ((a > c) && (a < b))) middle = a; if (((b > a) && (b < c)) || ((b > c) && (b < a))) middle = b; if (((c > b) && (c < a)) || ((c > a) && (c < b))) middle = c; if ((a == b) || (a==c)) middle = a; if (b == c) middle = b; System.out.println(middle);

Fadi AlSaidi

Level 13 , Carrollton, United States

16 November 2018, 21:00

no dice :(

Michael Martin

Level 19 , Arlington, United States

16 November 2018, 21:18

sorry, not sure then :(

Fadi AlSaidi

Level 13 , Carrollton, United States

17 November 2018, 00:13

it's ok thank you for your help. I get the idea and the practice behind it. now it's just an aimless puzzle

Thomas

Level 12 , Scottsdale, United States

3 June 2019, 21:20

Thanks Michael & Fadi !!

Thomas

Level 12 , Scottsdale, United States

3 June 2019, 21:21

See Fadi + Michael combo help !! I have to think more about this thing .....

olik09

Level 9 , Riyadh, Saudi Arabia

1 April 2020, 18:33

I think it wants you to print the middle number of "a" , "b" and "c" which is the number the user entered. However, you're printing "midnum" which is correct but not according to the task. try this:

if((a>=b && a<c) || (a>c && a<=b)){
             System.out.println(a);
    }
    else if((b>a && b<=c) || (b>=c && b<a)){
    System.out.println(b);
}
    else if ((c>=a && c<b) || (c>b && c<=a)){
    System.out.println(c);
}
else if(a == b && b == c){
    System.out.println(b);
}
}
}

Hoist

Level 32 , San Diego, United States

5 October 2021, 01:50

winner )) thx 09 nice and tight logic !